Solucionario Walpole 6 Edicion Gratis 55

Thus, (1, 2) represents the selection of 1 king and 2 jacks, which will come up with a probability of 4 4 1 6 f (1, 2) = 2 = 12 . 3 55 Continuing the same. consideration, we obtain in the general case the following set of choices: where p is the probability of “winning” all choices in this set.
Consider now the set of choices S, denoting by n the number of choices in S (n > 1). Since the number of choices in the set S depends on the choice of 1 and 2 kings, then for n 1 we get the following set of choices (for n = 2): and for n = 3 we get: moreover, according to the multiplication theorem, 2 n 3 = 2 n 2 . These results allow us to express the probability of winning each

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